The four values of the four weights are 1, 3, 9, and 27. My strategy for solving this question included a combination of reducing the problem into smaller parts and guessing/checking. To satisfy herbs of weight 1g-4g, I reduced that 1g and 3g would suffice. Then, in order to satisfy 40 grams, I concluded that the remaining weights should add up to 36 grams. I began testing, starting at 5g and 31g for my third and fourth weight. As I encountered gaps, I would systematically increase the third weight and restart my testing process. Ultimately, I landed at 1, 3, 9 and 27 as the answer. I was shocked to notice that these were the powers of 3.
Using the theme of powers, I immediately tested the powers of two for the second question. It also related to our previous decisions in the garden about Egyptian multiplication. We learned that any number may be represented using powers of two. Furthermore, 1+2+4+8+16=31 which met the criteria for the one scale problem. Thus, the five weights for the second problem are 1g, 2g, 4g, 8g, and 16g.I may extend the problem by getting students to explore how adding weights would increase the quantities of herbs we may weigh. Does this number go up at a constant rate? Exponential? Or something different? One may also have fractional weights consistent with the base system (i.e. ⅓, 1/9…) to examine how precise one may get with these quantities. Could we construct any fraction using base 3 fractions? Why or why not? Lastly, students may explore how the base changes when one adds or subtracts states of the question.
Overall, this puzzle connects with my prior knowledge of binary numbers. Specifically, it relates to the fact that any number may be represented using a binary system. Since a third state is added to this puzzle (left, right, or not included), we may similarly use a base 3 system.






